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(col(c)-col(B1))/(col(d)-col(a)) c ?>>C  deriv(col(B1)) c # mm̌?333333?(>>__WIPR (  m̌?333333?(  c #c5fffff?Կ(I>>__WIOTN (  Ifffff?Կ(I I o92 R A R B` R   R @ R  "&@% R @$ R   R  P R   R @ R  "&@$ R @$ R   R  P R  R  R  R  R  R  A1800sec* ^DLPC:\Origin,FrXXsC:\BIOCHEM 434 W2005\DIFFUSION\DIF002.DAT ^@?@"@2@?@l "$ (? ף= ף= Pd c #vg̜?y?(>>__WIPR (  g̜?y?(  c #c5fffff?Կ(I>>__WIOTN (  Ifffff?Կ(I I o92 R A R B` R   R @ R  "&@% R @$ R   R  P R   R @ R  "&@$ R @$ R   R  P R  R  R  R  R  R  A3600sec ^DLPC:\Origin,FrXXsC:\BIOCHEM 434 W2005\DIFFUSION\DIF004.DAT ^@?@"@?@l "$ (? ף= ף= Pd c 333333?55 >>E (col(d)-col(b))/(col(c)-col(a)) c #yi̠?UUUUUU?(>>__WIPR (  i̠?UUUUUU?(  c #c5fffff?Կ(I>>__WIOTN (  Ifffff?Կ(I I o92 R A R B` R   R @ R  "&@% R @$ R   R  P R   R @ R  "&@$ R @$ R   R  P R  R  R  R  R  R  A4500sec ^DLPC:\Origin,FrXXsC:\BIOCHEM 434 W2005\DIFFUSION\DIF005.DAT ^@?@"@?@l "$ (? ף= ף= Pd c # yo̠?wwwwww?(>>__WIPR (  o̠?wwwwww?(  c #c5fffff?Կ(I>>__WIOTN (  Ifffff?Կ(I I o92 R  A R  B ` R   R @ R  "&@% R @$ R   R  P R   R @ R  "&@$ R @$ R   R  P R  R  R  R  R  R  A2700sec% ^DLPC:\Origin,FrXXsC:\BIOCHEM 434 W2005\DIFFUSION\DIF003.DAT ^@?@"@?@l "$ (? ף= ף= Pd c # m?333333?(>>__WIPR (  m?333333?(  c #c5fffff?Կ(I>>__WIOTN (  Ifffff?Կ(I I o92 R A R B` R   R @ R  "&@% R @$ R   R  P R   R @ R  "&@$ R @$ R   R  P R  R  R  R  R  R  OLDREDIR @ I1  ' T  Notes D 0.15 mL of protein solution, in 0.15 M NaCl, 0.025 M Hepes, 0.001 M TCEP, pH 7.4, at 20 C, was placed in the sample compartment of a special double-sector cell called a synthetic-boundary cell. 0.4 mL of buffer was placed in the reference compartment. The cell was then centrifuged at 4000 rpm. The reference and sample chambers in the synthetic-boundary cell are connected by a very narrow channel. The centrifugal force generated as the sample spins drives solvent into the sample compartment until the liquid column heights are equalized. This has the effect of gently layering pure solvent over the sample, creating a sample-buffer interface. The decay of the interface, due to diffusion, is then monitored with time. Analyze the data contained in the five spreadsheets to obtain an estimate of the diffusion coefficient for this protein. General procedure: Fit each data set to sigmoidal Richards function type 2 (SRichards2). Before hitting DONE, simulate data with optimized parameters. (This adds a column containing the fit to the spreadsheet.) After fitting all five data sets, determine dc/dr values at the boundary: Plot column of fitted value. With graph active, go to analysis->calculus->differentiate. This command reates a column containing the derivative and plots the values in a graph called 'deriv'. Do this for each spreadsheet. You will end up with five curves on the 'deriv' graph. Read the values of the peak maxima. Plot (Co/(dc/dr))^2 for each of the ten data sets vs time. Slope equals 4*pi*D. Solve for D.